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2/(5^x)=3/(7^x)
We move all terms to the left:
2/(5^x)-(3/(7^x))=0
Domain of the equation: 5^x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 7^x)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
2/5^x-3/7^x=0
We calculate fractions
14x/35x^2+(-15x)/35x^2=0
We multiply all the terms by the denominator
14x+(-15x)=0
We get rid of parentheses
14x-15x=0
We add all the numbers together, and all the variables
-x=0
x=0/-1
x=0
Równanie nie ma rozwiązania
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